Tuesday, July 29, 2014

This is a post that tests Latex.

This is a new post.

$\frac{1}{2}$ is a Latex thing; don't know if it'll work.

Now let's try the quadratic formula:

$\frac{-b\pm\sqrt{b^2-4ac}}{2a}=x$ is the solution to $ax^2+bx+c$.

A system of equations:
$ax+by=c$
$dx+ey=f$

when
$x=0 and
y=0$

6 comments:

  1. I prefer having the quadratic formula written with $ x= $ first, like this:
    $ x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} $ .

    Apparently you can't put Latex in comments.

    ReplyDelete
  2. Now I'm going to try and do this with LaTeX:

    $ x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} $. I hope that's the correct way of solving $ax^2+bx+c=0$ where $a\ne0$.

    ReplyDelete
  3. $ \frac{-b\pm\sqrt{b^2-4ac}}{2a} $

    ReplyDelete
  4. $ x = \frac{-b\pm\sqrt{b^2-4ac}}{2a} $

    ReplyDelete
  5. $ \frac{-b\pm\sqrt{b^2-4ac}}{2a} = x $ is not the best way to write this.

    I think that $ x = \frac{-b\pm\sqrt{b^2-4ac}}{2a} $ is better and I wonder if you can put more than one LaTeX per line.
    $a \ne 0$

    $a\ne0$

    $a\ne0$ and $b\ne0$ and $c\ne0$.

    ReplyDelete